BÀI LÀM
Câu 115:
Phương trình hoá học:
a)Điều chế CuO:
-C1: [imath]Cu(OH)_2 \overset{t^o}\to CuO + H_2O[/imath];
-C2: [imath]2Cu + O_2 \to 2CuO[/imath];
+Điều chế MgO:
-C1: [imath]Mg(OH)_2 \overset{t^o}\to MgO + H_2O[/imath];
-C2: [imath]2Mg + O_2 \to 2MgO[/imath];
b)Điều chế [imath]SO_2[/imath]:
-C1: [imath]S + O_2 \overset{t^o}\to SO_2\uparrow[/imath];
-C2: [imath]Cu + 2H_2SO_{4_{đăc}} \overset{t^o}\to CuSO_4 + 2H_2O + SO_2\uparrow[/imath];
-C3: [imath]K_2SO_3 + 2HCl \to 2KCl + H_2O + SO_2\uparrow[/imath];
Điều chế [imath]CO_2[/imath]:
-C1: [imath]C + O_2 \overset{t^o}\to CO_2\uparrow[/imath];
-C2: [imath]Na_2CO_3 + 2HCl \overset{t^o}\to 2NaCl + H_2O + CO_2\uparrow[/imath];
-C3: [imath]CuCO_3 + 2HNO_3 \to Cu(NO_3)_2 + H_2O + CO_2\uparrow[/imath];
c)ĐIều chế HCl:
-C1: [imath]H_2 + Cl_2 \to 2HCl\uparrow[/imath];
-C2: [imath]BaCl_2 + H_2SO_4 \to BaSO_4 + 2HCl[/imath];
ĐIều chế [imath]H_2S[/imath]:
-C1: [imath]CuS + 2HCl \to CuCl_2 + H_2S\uparrow[/imath];
-C2: [imath]Na_2S + 2HCl \to 2NaCl + H_2S\uparrow[/imath]
ĐIều chế [imath]H_3PO_4[/imath]:
-C1: [imath]P_2O_5 + 3H_2O \to 2H_3PO_4[/imath];
-C2: [imath]Ca_3(PO_4)_2 + 6HCl \to 3CaCl_2 + 2H_3PO_4[/imath];
Điều chế [imath]HNO_3[/imath]:
-C1:
-C2:
Điều chế [imath]H_2SO_4[/imath]:
-C1: [imath]SO_3 + H_2O \to H_2SO_4[/imath];
-C2:
d) Điều chế NaOH:
-C1: [imath]2Na + 2H_2O \to 2NaOH + H_2\uparrow[/imath];
-C2: [imath]Na_2O + H_2O \to 2NaOH[/imath];
-C3: [imath]Ba(OH)_2 + Na_2SO_4 \to BaSO_4\downarrow + 2NaOH[/imath];
-C4: [imath]Ca(OH)_2 + Na_2CO_3 \to CaCO_3\downarrow + 2NaOH[/imath];
Điều chế [imath]Ca(OH)_2[/imath]:
-C1: [imath]Ca + 2H_2O \to Ca(OH)_2 + H_2\uparrow[/imath];
-C2: [imath]CaO + H_2O \to Ca(OH)_2[/imath];
-C3: [imath]CaSO_4 + Ba(OH)_2 \to BaSO_4\downarrow + Ca(OH)_2[/imath];
-C4:
Điều chế [imath]Al(OH)_3[/imath]:
-C1: [imath]AlCl_3 + 3NaOH \to Al(OH)_3\downarrow + 3NaCl[/imath];
-C2: [imath]Al_2(SO_4)_3 + 6NaOH \to 2Al(OH)_3\downarrow + 3Na_2SO_4[/imath];
-C3: [imath]Al(NO_3)_3 + 3NaOH \to Al(OH)_3\downarrow + 3NaNO_3[/imath];
-C4:
e)Điều chế [imath]FeCl_2[/imath]:
-C1: [imath]Fe + 2HCl \to F eCl_2 + H_2\uparrow[/imath];
-C2: [imath]FeSO_4 + BaCl_2 \to FeCl_2 + BaSO_4\downarrow[/imath];
-C3: [imath]2FeCl_3 + Fe \to 3FeCl_2[/imath];
-C4:
-C5:
-C6:
Điều chế [imath]CuSO_4[/imath]:
-C1: [imath]Cu + 2H_2SO_{4_{đăc}} \overset{t^o}\to CuSO_4 + 2H_2O + SO_2\uparrow[/imath];
-C2: [imath]CuCl_2 + Ag_2SO_4 \to CuSO_4 + 2AgCl\downarrow[/imath];
-C3:
-C4:
-C5:
-C6:
f)Điều chế khí [imath]Cl_2[/imath]:
-C1: [imath]2NaCl \overset{đpnc}\to 2Na + Cl_2\uparrow[/imath];
-C2: [imath]2KCl \overset{đpnc}\to 2K + Cl_2\uparrow[/imath];
-C3: [imath]CuCl_2 \overset{đpdd}\to Cu + Cl_2\uparrow[/imath];
-C4: [imath]2FeCl_3 \overset{đpdd}\to 2Fe + 3Cl_2\uparrow[/imath];
g)Điều chế khí HCl:
-C1: [imath]H_2 + Cl_2 \to 2HCl[/imath];
-C2:
-C3:
-C4:
Câu 116:
Phương trình hoá học:
[imath]4P + 5O_2 \overset{t^o}\to 2P_2O_5[/imath];
[imath]P_2O_5 + 3H_2O \to 2H_3PO_4[/imath];