BD Hóa 8 Bài tập chuỗi phương trình (Yến)

[Master]

Hoàn thành các chuỗi phương trình sau:

Lưu ý làm đúng thứ tự đã đánh dấu. không làm đảo trật tự vì làm thế khó sửa bài. PT nào ko biết thì cứ ghi thứ tự rồi để trống. khi sửa chỉ sửa những PT viết sai thôi.

 

[Ái Quỳnh]

BÀI LÀM:
Câu 1:
(1): [imath]2Ca+O_2\overset{t^o}\rightarrow2 CaO[/imath]
(2):[imath]CaO +H_2O\rightarrow Ca(OH)_2[/imath]
(3):[imath]Ca(OH)_2+ CO_2 \rightarrow CaCO_3 +H_2O[/imath]
(4):[imath]CaCO_3 +H_2O+CO_2 \rightarrow Ca(HCO_3)_2[/imath]
(5):[imath]Ca(HCO_3)_2 +2HCl\rightarrow CaCl_2 +2H_2O+2CO_2\uparrow[/imath]
(6):[imath]CaCl_2 +K_2CO_3\rightarrow CaCO_3 \downarrow +2KCl[/imath]
Câu 2:
(1):[imath]Fe+2HCl \rightarrow FeCl_2 +H_2\uparrow[/imath]
(2):
(3):[imath]FeSO_4+Ba(NO_3)_2\rightarrow Fe(NO_3)_2+BaSO_4\downarrow[/imath]
(4):[imath]Fe(NO_3)_2 +NaOH\rightarrow Fe(OH)_2 \downarrow +NaNO_3[/imath]
[imath]Fe(OH)_2 +AgNO_3 \rightarrow Ag_2O \downarrow+H_2O +Fe(NO_3)_2[/imath]
(5):
(6):[imath]2Fe+3Cl_2 \overset {t^o}\rightarrow 2FeCl_3[/imath]
(7):
(8):[imath]Fe_2(SO_4)_3 +3Ba(NO_3)_2 \rightarrow 3BaSO_4 \downarrow+2Fe(NO_3)_3[/imath]
(9):[imath]2Fe(NO_3)_3 +3Ca(OH)_2 \rightarrow 3Ca(NO_3)_2 +2Fe(OH)_3\downarrow[/imath]
(10):[imath]2Fe(OH)_3 +3Cu(NO_3)_2\rightarrow 2Fe(NO_3)_3 +3Cu(OH)_2\downarrow[/imath]
(11):[imath]2Fe(OH)_3 \overset{t^o}\rightarrow Fe_2O_3\downarrow +3H_2O[/imath]
(12):[imath]4Fe(OH)_2 +2H_2O +O_2\rightarrow 4Fe(OH)_3[/imath]
(13):[imath]Fe(NO_3)_2 +2{{HNO_3}_{đặc nóng}} \rightarrow Fe(NO_3)_3 +NO_2 \uparrow+H_2O[/imath]
(14):[imath]2Fe(NO_3)_3 +Cu\rightarrow 2Fe(NO_3)_2+Cu(NO_3)_2[/imath]
(15):[imath]2FeSO_4 +2 {{H_2SO_4}_{đặc nóng}} \rightarrow Fe_2(SO_4)_3 +2H_2O+SO_2\uparrow[/imath]
(16):[imath]Fe_2(SO_4)_3 +Fe\rightarrow 3FeSO_4[/imath]
(17):[imath]2FeCl_3+Fe\rightarrow 3FeCl_2[/imath]
(18):[imath]2FeCl_2+Cl_2 \rightarrow 2FeCl_3[/imath]
Câu 3:
(1):[imath]4FeS_2 +11O_2 \overset{t^o}\rightarrow 2Fe_2O_3 +8SO_2\uparrow[/imath]
(2):[imath]2SO_2 +O_2\overset{t^o,V_2O_5}\rightarrow2SO_3[/imath]
(3):[imath]SO_3+H_2O\rightarrow H_2SO_4[/imath]
(4):[imath]Cu+{{2H_2SO_4}_{đặc nóng}} \rightarrow CuSO_4 +SO_2\uparrow +2H_2O[/imath]
(5):
(6):[imath]NaHSO_3 +NaOH \rightarrow Na_2SO_3 +H_2O[/imath]

 

[Phạm Anh Thư]

Câu 1:
(1) [imath]2Ca+ O_2 \overset{t^o}{\rightarrow} 2CaO[/imath]
(2) [imath]CaO+ H_2O \to Ca(OH)_2[/imath]
(3) [imath]Ca(OH)_2+ Na_2CO_3 \to CaCO_3 + 2NaOH[/imath]
(4) [imath]CaCO_3 + CO_2 + H_2O \to Ca(HCO_3)_2[/imath]
(5) [imath]Ca(HCO_3)_2 + 2HCl \to CaCl_2 + 2H_2O + 2CO_2[/imath]
(6) [imath]CaCl_2 + Na_2CO_3 \to CaCO_3 + 2NaCl[/imath]
Câu 2:
(1) [imath]Fe+ 2HCl \to FeCl_2 + H_2[/imath]
(2) [imath]FeCl_2 + H_2SO_4 \to FeSO_4 + 2HCl[/imath]
(3) [imath] FeSO_4 + Ba(NO_3)_2 \to Fe(NO_3)_2 + BaSO_4[/imath]
(4) [imath] Fe(NO_3)_2 +2NaOH \to Fe(OH)_2+ 2NaNO_3[/imath]
[imath] Fe(OH)_2 + 2HNO_3 \to Fe(NO_3)_2 + 2H_2O[/imath]
(5) [imath] Fe(OH)_2 \overset{t^o}{\rightarrow} FeO+ H_2O [/imath]
(6) [imath] 2Fe + 3Cl_2 \to 2FeCl_3[/imath]
(7) [imath]2FeCl_3 + 3H_2SO_4 \to Fe_2(SO_4)_3+ 6HCl[/imath]
(8) [imath] Fe_2(SO_4)_3 + 6HNO_3 \to 2Fe(NO_3)_3 + 3H_2SO_4[/imath]
(9) [imath] Fe(NO_3)_3 + 3NaOH \to Fe(OH)_3+ 3NaNO_3[/imath]
(10) [imath] Fe(OH)_3+ 3HNO_3 \to Fe(NO_3)_3 + 3H_2O [/imath]
(11) [imath] 2Fe(OH)_3 \overset{t^o}{\rightarrow} Fe_2O_3 + 3H_2O [/imath]
(12)
(13) [imath]6Fe(NO_3)_2 + 3Cl_2 \to 4Fe(NO_3)_3+ 2FeCl_3[/imath]
(14) [imath]2Fe(NO_3)_3 + Cu \to 2Fe(NO_3)_2 + Cu(NO_3)_2[/imath]
(15) [imath]6FeSO_4 + 3Cl_2 \to 2Fe_2(SO_4)_3 + 2FeCl_3[/imath]
(16) [imath]Fe_2(SO_4)_3 + Cu \to 2FeSO_4 + CuSO_4[/imath]
(17) [imath]2FeCl_3 + Fe \to 3FeCl_2 [/imath]
(18) [imath]2FeCl_2 + Cl_2 \to 2FeCl_3[/imath]
Câu 3:
(1) [imath]4FeS_2 + 11O_2 \overset{t^o}{\rightarrow} 2Fe_2O_3 + 8SO_2[/imath]
(2) [imath]2SO_2 + O_2 \overset{t^o}{\rightarrow} 2SO_3[/imath]
(3) [imath]SO_3 + H_2O \to H_2SO_4[/imath]
(4) [imath]H_2SO_4 + Na_2SO_3 \to Na_2SO_4 + H_2O + SO_2[/imath]
[imath]Na_2SO_3 + 2HNO_3 \to 2NaNO_3 + H_2O + SO_2[/imath]
(5) [imath]SO_2 + NaOH \to NaHSO_3[/imath]
(6) [imath]NaHSO_3 + NaOH \to Na_2SO_3 + H_2O[/imath]

 

[Minh Thái]

BÀI LÀM​

Bài 1:
1) [imath]2Ca+O_2\overset{t^o}\to 2CaO[/imath]
2) [imath]CaO+H_2O\to Ca(OH)_2[/imath]
3) [imath]Ca(OH)_2+Na_2CO_3\to CaCO_3+2NaOH[/imath]
4) [imath]CaCO_3+CO_2+H_2O\to Ca(HCO_3)_2[/imath]
5)
6) [imath]CaCl_2+H_2CO_3\to CaCO_3+2HCl[/imath]
Bài 2:
1) [imath]Fe+2HCl\to FeCl_2+H_2[/imath]
2) [imath]FeCl_2+Ag_2SO_4\to FeSO_4+2AgCl[/imath]
3) [imath]FeSO_4+2HNO_3\to Fe(NO_3)_2+H_2SO_4[/imath]
4) [imath]Fe(NO_3)_2+2NaOH\to Fe(OH)_2+2NaNO_3[/imath]
5)
6) [imath]2Fe+3Cl_2\overset{t^o}\to 2FeCl_3[/imath]
7) [imath]4FeCl_3+6Ag_2SO_4\to 2Fe_2(SO_4)_3+12AgCl[/imath]
8) [imath]Fe_2(SO_4)_3+3Ba(NO_3)_2\to 2Fe(NO_3)_3+3BaSO_4[/imath]
9) [imath]Fe(NO_3)_3+Al(OH)_3\to Al(NO_3)_3+Fe(OH)_3[/imath]
10) [imath]Fe(OH)_3+Al(NO_3)_3\to Fe(NO_3)_3+Al(OH)_3[/imath]
11) [imath]2Fe(OH)_3\overset{t^o}\to Fe_2O_3+3H_2O[/imath]
12) [imath]4Fe(OH)_2+O_2+2H_2O\to 4Fe(OH)_3[/imath]
13) [imath]Fe(NO_3)_2+AgNO_3\to Ag+Fe(NO_3)_3[/imath]
14) [imath]2Fe(NO_3)_3+Fe\to 3Fe(NO_3)_2[/imath]
15) [imath]6FeSO_4+3Cl_2\to 2Fe_2(SO_4)_3+2FeCl_3[/imath]
16) [imath]Fe_2(SO_4)_3+Fe\to 3FeSO_4[/imath]
17) [imath]2FeCl_3+Fe\to 3FeCl_2[/imath]
18) [imath]2FeCl_2+Cl_2\to 2FeCl_3[/imath]
Bài 3:
1) [imath]4FeS_2+11O_2\overset{t^o}\to 2Fe_2O_3+8SO_2[/imath]
2) [imath]2SO_2+O_2\overset{V_2O_5,450^oC}\to 2SO_3[/imath]
3) [imath]SO_3+H_2O\to H_2SO_4[/imath]
4)
5) [imath]Na_2SO_3+SO_2+H_2O\to 2NaHSO_3[/imath]
6) [imath]NaHSO_3+NaOH\to Na_2SO_3+H_2O[/imath]

 

[Phương Dung]

1.
(1) [imath]2Ca+O_2 \overset{t^o}\rightarrow 2CaO[/imath]
(2) [imath]CaO+H_2O \to Ca(OH)_2[/imath]
(3) [imath]Ca(OH)_2+H_2O+CO_2 \to CaCO_3 \downarrow+2H_2O[/imath]
(4) [imath]Ca_2CO_3+CO_2+H_2O \to Ca(HCO_3)_2[/imath]
(5)
(6) [imath]CaCl_2+Na_2CO_3 \to CaCO_3 \downarrow+2NaCl[/imath]
2.
(1) [imath]Fe+CuCl_2 \to FeCl_2+Cu[/imath]
(2) [imath]FeCl_2+Ag_2SO_4 \to FeSO_4+2AgCl \downarrow[/imath]
(3) [imath]FeSO_4+Ba(NO_3)_2 \to Fe(NO_3)_2+BaSO_4 \downarrow[/imath]
(4) [imath]Fe(NO_3)_2+2NaOH \to Fe(OH)_2 \downarrow+2NaNO_3[/imath]
[imath]Fe(OH)_2+2AgNO_3 \to 2AgOH+Fe(NO_3)_2[/imath]
(5)
(6) [imath]2Fe+3Cl_2 \overset{t^o}\rightarrow 2FeCl_3[/imath]
(7) [imath]2FeCl_3+3Ag_2SO_4 \to Fe_2(SO_4)_3 + 6AgCl \downarrow[/imath]
(8) [imath]Fe_2(SO_4)_3+3Ba(NO_3)_2 \to 2Fe(NO_3)_3+3BaSO_4 \downarrow[/imath]
(9) [imath]Fe(NO_3)_3+3NaOH \to Fe(OH)_3 \downarrow3NaNO_3[/imath]
(10)[imath]Fe(OH)_3+3AgNO_3 \to 3AgOH+Fe(NO_3)_3[/imath]
(11) [imath]Fe(OH)_2 \overset{t^o}\rightarrow Fe_2O_3+H_2O[/imath]
(12) [imath]4Fe(OH)_2 + O_2 + 2H_2O \rightarrow 4Fe(OH)_3[/imath]
(13) [imath]6Fe(NO_3)_2+3Cl_2 \to 4Fe(NO_3)_3+ 2FeCl_3[/imath]
(14) [imath]2Fe(NO_3)_3+ Fe \to 3Fe(NO_3)_2[/imath]
(15) [imath]6FeSO_4+3Cl_2 \to 2Fe_2(SO_4)_3+2FeCl_3[/imath]
(16) [imath]Fe_2(SO_4)_3+3Fe \to 3FeSO_4[/imath]
(17) [imath]2FeCl_3+Cu \to 2FeCl_2+CuCl_2 [/imath]
(18) [imath]2FeCl_2+Cl_2 \to 2FeCl_3[/imath]
3.
(1) [imath]4FeS_2+11O_2 \to 2Fe_2O_3+8SO_2[/imath]
(2) [imath]SO_2+O_2 \overset{450^oC, P_2O_5}\rightarrow SO_3[/imath]
(3) [imath]SO_3+H_2O \to H_2SO_4[/imath]
(4)
(5) [imath]SO_2+Na_2CO_3+H_2O \to NaHCO_3[/imath]
(6) [imath]NaHSO_3+NaOH \to Na_2SO_3+H_2O[/imath]

 

[Minh Đăng]

BÀI LÀM​

Câu 1:
(1): [imath]2Ca + O_2 \overset{t^o}\to 2CaO[/imath].
(2): [imath]CaO + H_2O \to Ca(OH)_2[/imath].
(3): [imath]Ca(OH)_2 + CO_2 \to CaCO_3\downarrow + H_2O[/imath].
(4): [imath]CaCO_3 + CO_2 + H_2O \to Ca(HCO_3)_2[/imath].
(5): [imath]Ca(HCO_3)_2 + 2HCl \to CaCl_2 + 2H_2O + 2CO_2\uparrow[/imath].
(6): [imath]CaCl_2 + Na_2CO_3 \to CaCO_3\downarrow + 2NaCl[/imath].
Câu 2:
(1): [imath]Fe + 2HCl \to FeCl_2 + H_2\uparrow[/imath].
(2):
(3): [imath]FeSO_4 + 2NaNO_3 \to Fe(NO_3)_2 + Na_2SO_4[/imath].
(4): [imath]Fe(NO_3)_2 + 2NaOH \to Fe(OH)_2\downarrow + 2NaNO_3[/imath].
(5): [imath]4Fe(OH)_2 + O_2 \overset{t^o}\to 2Fe_2O_3 + 4H_2O[/imath].
(6): [imath]2Fe + 3Cl_2 \overset{t^o}\to 2FeCl_3[/imath].
(7):
(8): [imath]Fe_2(SO_4)_3 + 3Ba(NO_3)_2 \to 2Fe(NO_3)_3 + 3BaSO_4\downarrow[/imath].
(9): [imath]Fe (NO_3)_3 + 3NaOH \to Fe(OH)_3\downarrow + 3NaNO_3[/imath].
(10): [imath]2Fe(OH)_3 + 6HNO_3 \to 2Fe(NO_3)_3 + 6H_2O[/imath].
(11): [imath]2Fe(OH)_3 \overset{t^o}\to Fe_2O_3 + 3H_2O[/imath].
(12): [imath]Fe(OH)_2 + O_2 + 2H_2O \to Fe(OH)_3[/imath].
(13): [imath]Fe(NO_3)_2 + 2HNO_3\to Fe(NO_3)_3 + NO_2 + H_2O[/imath].
(14): [imath]2Fe(NO_3)_3 + Fe \to 3Fe(NO_3)_2[/imath].
(15): [imath]6FeSO_4 + 3Cl_2 \to 2Fe_2(SO_4)_3 + 2FeCl_3[/imath].
(16): [imath]Fe_2(SO_4)_3 + Fe \to 3FeSO_4[/imath].
(17): [imath]2FeCl_3 + Fe \to 3FeCl_2[/imath].
(18): [imath]2FeCl_2 + Cl_2 \to 2FeCl_3[/imath].
Câu 3:
(1): [imath]4FeS_2 + 11O_2 \overset{t^o}\to 2Fe_2O_3 + 8SO_2\uparrow[/imath].
(2): [imath]2SO_2 + O_2 \overset{450^oC, V_2O_5}\to 2SO_3\uparrow[/imath].
(3): [imath]SO_3 + H_2O \to H_2SO_4[/imath].
(4): [imath]2H_2SO_{4_{đăc}} + Cu \overset{t^o}\to CuSO_4 + 2H_2O + SO_2\uparrow[/imath].
[imath]Na_2SO_3 + 2HCl \to 2NaCl + H_2O + SO_2\uparrow[/imath].
(5): [imath]SO_2 + NaOH \to NaHSO_3[/imath].
(6): [imath]NaHSO_3 + NaOH \to Na_2SO_3 + H_2O[/imath].

 

[Ái Quỳnh]

BÀI LÀM :
Câu 1:
(1):[imath]2Ca+O_2 \overset{t^o}\rightarrow 2CaO[/imath]
(2):[imath]CaO+H_2O\rightarrow Ca(OH)_2[/imath]
(3)[imath]Ca(OH)_2 +CO_2 \rightarrow CaCO_3 +H_2O[/imath]
(4):
(5): [imath]Ca(HCO_3)_2 +2HCl\rightarrow CaCl_2+2H_2O+CO_2\uparrow[/imath]
(6)[imath]CaCl_2+Na_2CO_3 \rightarrow 2NaCl+CaCO_3\downarrow[/imath]
Câu 2:
(1):[imath]Fe+2HCl\rightarrow FeCl_2 +H_2\uparrow[/imath]
(2):
(3):[imath]FeSO_4+Ba(NO_3)_2 \rightarrow Fe(NO_3)_2 +BaSO_4\downarrow[/imath]
(4):[imath]Fe(NO_3)_2 +NaOH\rightarrow NaNO_3+Fe(OH)_2\downarrow[/imath]
[imath]Fe(OH)_2 +2AgNO_3 \rightarrow Fe(NO_3)_2 +Ag_2O+H_2O[/imath]
(5):
(6)[imath]2Fe+3Cl_2 \overset{t^o}\rightarrow2 FeCl_3[/imath]
(7)
(8):[imath]Fe_2(SO_4)_3 +3Ba(NO_3)_2 \rightarrow 2Fe(NO_3)_3 +3BaSO_4[/imath]
(9)[imath](2Fe(NO_3)_3 +3Ca(OH)_2\rightarrow 3Ca(NO_3)_2+2Fe(OH)_3\downarrow[/imath]
(10)[imath]2Fe(OH)_3 +3Mg(NO_3)_2 \rightarrow 2Fe(NO_3)_3+3Mg(OH)_2[/imath]
(11)[imath]2Fe(OH)_3 \overset{t^o}\rightarrow Fe_2O_3+3H_2O[/imath]
(12)[imath]4Fe(OH)_2 +2H_2O +O_2 \rightarrow 4Fe(OH)_3[/imath]
(13)[imath]Fe(NO_3)_2 +2HNO_3 \rightarrow Fe(NO_3)_3 +H_2O+NO_2[/imath]
(14)[imath]2Fe(NO_3)_3 +Fe\rightarrow3 Fe(NO_3)_2[/imath]
(15)[imath]FeSO_4 +H_2SO_4 \rightarrow Fe_2(SO_4)_3 +H_2O+SO_2\uparrow[/imath]
(16)[imath]Fe_2(SO_4)_3 +Cu\rightarrow CuSO_4+2FeSO_4[/imath]
(17)[imath]2FeCl_3+Fe\rightarrow 3FeCl_2[/imath]
(18)[imath]2FeCl_2+Cl_2\rightarrow2 FeCl_3[/imath]
Câu 3:
(1): [imath]4FeS_2+11O_2 \overset{t^o}\rightarrow 2 Fe_2O_3+8SO_2[/imath]
(2)[imath]2SO_2 +O_2 \overset{t^o}\rightarrow 2SO_3[/imath]
(3)[imath]SO_3+H_2O\rightarrow H_2SO_4[/imath]
(4): [imath]Cu+2{{H_2SO_4}_{đặc nóng}} \rightarrow CuSO_4 +2H_2O+SO_2[/imath]
(5):
(6)

 

[Ái Quỳnh]

BÀI SỬA:
Câu 1:
(1):[imath]2Ca+O_2 \overset{t^o}\rightarrow 2CaO[/imath]
(2):[imath]CaO+H_2O\rightarrow Ca(OH)_2[/imath]
(3)[imath]Ca(OH)_2 +CO_2 \rightarrow CaCO_3 +H_2O[/imath]
(4):[imath]CaCO_3 + CO_2 + H_2O \to Ca(HCO_3)_2[/imath]
(5): [imath]Ca(HCO_3)_2 +2HCl\rightarrow CaCl_2+2H_2O+2CO_2\uparrow[/imath]
(6) [imath]CaCl_2+Na_2CO_3 \rightarrow 2NaCl+CaCO_3\downarrow[/imath]
Câu 2:
(1): [imath]Fe+2HCl\rightarrow FeCl_2 +H_2\uparrow[/imath]
(2):
(3): [imath]FeSO_4+Ba(NO_3)_2 \rightarrow Fe(NO_3)_2 +BaSO_4\downarrow[/imath]
(4): [imath]Fe(NO_3)_2 +2NaOH\rightarrow 2NaNO_3+Fe(OH)_2\downarrow[/imath]
[imath]Fe(OH)_2 +2AgNO_3 \rightarrow Fe(NO_3)_2 +Ag_2O+H_2O[/imath]
(5): 4[imath]Fe(OH)_2 +O_2\overset{t^o} \rightarrow 2Fe_2O_3 +4H_2O[/imath]
(6): [imath]2Fe+3Cl_2 \overset{t^o}\rightarrow2 FeCl_3[/imath]
(7)
(8): [imath]Fe_2(SO_4)_3 +3Ba(NO_3)_2 \rightarrow 2Fe(NO_3)_3 +3BaSO_4[/imath]
(9): [imath]2Fe(NO_3)_3 +3Ca(OH)_2\rightarrow 3Ca(NO_3)_2+2Fe(OH)_3\downarrow[/imath]
(10): [imath]2Fe(OH)_3 +3Mg(NO_3)_2 \rightarrow 2Fe(NO_3)_3+3Mg(OH)_2[/imath]
(11): [imath]2Fe(OH)_3 \overset{t^o}\rightarrow Fe_2O_3+3H_2O[/imath]
(12):[imath]4Fe(OH)_2 +2H_2O +O_2 \rightarrow 4Fe(OH)_3[/imath]
(13):[imath]Fe(NO_3)_2 +2HNO_3 \rightarrow Fe(NO_3)_3 +H_2O+NO_2[/imath]
(14):[imath]2Fe(NO_3)_3 +Fe\rightarrow3 Fe(NO_3)_2[/imath]
(15):[imath]FeSO_4 +H_2SO_4 \rightarrow Fe_2(SO_4)_3 +H_2O+SO_2\uparrow[/imath]
(16):[imath]Fe_2(SO_4)_3 +Cu\rightarrow CuSO_4+2FeSO_4[/imath]
(17):[imath]2FeCl_3+Fe\rightarrow 3FeCl_2[/imath]
(18):[imath]2FeCl_2+Cl_2\rightarrow2 FeCl_3[/imath]
Câu 3:
(1): [imath]4FeS_2+11O_2 \overset{t^o}\rightarrow 2 Fe_2O_3+8SO_2[/imath]
(2): [imath]2SO_2 +O_2 \overset{450^oC-500^oC,V_2O_5}\rightarrow 2SO_3[/imath]
(3): [imath]SO_3+H_2O\rightarrow H_2SO_4[/imath]
(4): [imath]Cu+2{{H_2SO_4}_{đặc nóng}} \rightarrow CuSO_4 +2H_2O+SO_2[/imath]
[imath]Na_2SO_3 +H_2SO_4 \rightarrow Na_2SO_4 +H_2O+SO_2 \uparrow[/imath]
(5): [imath]SO_2 + NaOH \to NaHSO_3[/imath]
(6): [imath]NaHSO_3 + NaOH \to Na_2SO_3 + H_2O[/imath].

 

[Minh Thái]

Bổ sung:
Bài 3:
4) [imath]H_2SO_4+CaSO_3\to CaSO_4+H_2O+SO_2[/imath]
[imath]Na_2SO_3+2HCl\to 2NaCl+H_2O+SO_2[/imath]

 

[Hải Yến]

Câu 2:
(2) [imath]FeCl_2 + H_2SO_4 \to FeSO_4 + 2HCl[/imath]
(5) [imath] Fe(OH)_2 \overset{t^o}{\rightarrow} FeO+ H_2O [/imath]
(7) [imath]2FeCl_3 + 3H_2SO_4 \to Fe_2(SO_4)_3+ 6HCl[/imath]
(8) [imath] Fe_2(SO_4)_3 + 6HNO_3 \to 2Fe(NO_3)_3 + 3H_2SO_4[/imath]

Câu 1 Thư làm đúng; câu 2 pt (2), (5), (7), (8) sai; câu 3: pt (2) xúc tác là [imath]V_2O_5[/imath]

BÀI LÀM​

Bài 1:
6) [imath]CaCl_2+H_2CO_3\to CaCO_3+2HCl[/imath]
Bài 2:
3) [imath]FeSO_4+2HNO_3\to Fe(NO_3)_2+H_2SO_4[/imath]
7) [imath]4FeCl_3+6Ag_2SO_4\to 2Fe_2(SO_4)_3+12AgCl[/imath]
9) [imath]Fe(NO_3)_3+Al(OH)_3\to Al(NO_3)_3+Fe(OH)_3[/imath]
10) [imath]Fe(OH)_3+Al(NO_3)_3\to Fe(NO_3)_3+Al(OH)_3[/imath]

Câu 1: pt (6) sai; câu 2: pt (3), (9), (10) sai, cân bằng lại pt (7) nhé; câu 3 đúng.

1.
(3) [imath]Ca(OH)_2+H_2O+CO_2 \to CaCO_3 \downarrow+2H_2O[/imath]
2.
(4)
[imath]Fe(OH)_2+2AgNO_3 \to 2AgOH+Fe(NO_3)_2[/imath]
(10)[imath]Fe(OH)_3+3AgNO_3 \to 3AgOH+Fe(NO_3)_3[/imath]
(11) [imath]Fe(OH)_2 \overset{t^o}\rightarrow Fe_2O_3+H_2O[/imath]
3.
(2) [imath]SO_2+O_2 \overset{450^oC, P_2O_5}\rightarrow SO_3[/imath]

Câu 1 cân bằng lại pt (3) nhé; câu 2: pt (4) ở dưới sai, pt (10), (11) sai; câu 3 pt (2) xúc tác là [imath]V_2O_5[/imath] nhé, các câu còn lại đúng.

BÀI LÀM​

Câu 2:
(3): [imath]FeSO_4 + 2NaNO_3 \to Fe(NO_3)_2 + Na_2SO_4[/imath].
(10): [imath]2Fe(OH)_3 + 6HNO_3 \to 2Fe(NO_3)_3 + 6H_2O[/imath].

Câu 1 đúng; câu 2: pt (3) sai chú ý cân bằng lại pt (10); câu 3 đúng.

BÀI LÀM :
Câu 2:
(4)
[imath]Fe(OH)_2 +2AgNO_3 \rightarrow Fe(NO_3)_2 +Ag_2O+H_2O[/imath]
(10)[imath]2Fe(OH)_3 +3Mg(NO_3)_2 \rightarrow 2Fe(NO_3)_3+3Mg(OH)_2[/imath]
(15)[imath]FeSO_4 +H_2SO_4 \rightarrow Fe_2(SO_4)_3 +H_2O+SO_2\uparrow[/imath]

Câu 1 đúng; Câu 2: pt (4) ở dưới sai, pt (10) sai, pt (15) chú ý ghi rõ [imath]H_2SO_4[/imath] đặc; câu 3: đúng

 

[Hải Yến]

Câu 2:
(5) [imath]4Fe(OH)_2 + O_2 \overset{t^0}\to 2Fe_2O_3 + 4H_2O[/imath]
Các chất kết tủa hoặc không tan không phản ứng với dd muối. Chú ý xem kĩ lại các tính chất hóa học của axit, bazơ, muối, điều kiện của phản ứng trao đổi nhé.
Sửa lại đề bài:
Câu 2:
Phương trình (4) ở dưới sửa lại thành [imath]Fe(OH)_2 \to Fe(NO_3)_3[/imath] nhé.

 

[Minh Thái]

BÀI SỬA​

Câu 1:
(5) [imath]Ca(HCO_3)_2+2HCl\to CaCl_2+2H_2O+2CO_2[/imath]
(6) [imath]CaCl_2+Na_2CO_3\to CaCO_3+2NaCl[/imath]
Câu 2:
(3) [imath]FeSO_4+Ba(NO_3)_2\to Fe(NO_3)_2+BaSO_4[/imath]
(5) [imath]4Fe(OH)_2+O_2 \overset{t^o}\to2Fe_2O_3+4H_2O[/imath]
(7) [imath]2FeCl_3+3Ag_2SO_4\to Fe_2(SO_4)_3+6AgCl[/imath]
(9) [imath]Fe(NO_3)_3+3NaOH\to Fe(OH)_3+3NaNO_3[/imath]
(10) [imath]Fe(OH)_3+3HNO_3\to Fe(NO_3)_3+3H_2O[/imath]

 

[Phạm Anh Thư]

Bài sửa​

Câu 2:
(2) [imath]FeCl_2 + Ag_2SO_4 \to FeSO_4 + 2AgCl[/imath]
(5) [imath] 4Fe(OH)_2 + O_2 \overset{t^o}{\rightarrow} 2Fe_2O_3+ 4H_2O [/imath]
(7) [imath]2FeCl_3 + 3Ag_2SO_4 \to Fe_2(SO_4)_3+ 6AgCl[/imath]
(8) [imath] Fe_2(SO_4)_3 + 3Ba(NO_3)_2 \to 2Fe(NO_3)_3 + 3BaSO_4[/imath]
(12)[imath]4Fe(OH)_2 + 2H_2O + O_2 \to 4Fe(OH)_3[/imath]
Câu 3:
(2) [imath]2SO_2 + O_2 \overset{V_2O_5}{\rightarrow} 2SO_3[/imath]

 

[Ái Quỳnh]

BÀI SỬA:
Câu 2:
(4):[imath]Fe(OH)_2 +Cu(NO_3)_2 \rightarrow Fe(NO_3)_2 +Cu(OH)_2\downarrow[/imath]
(10):[imath]Fe(OH)_3+3HNO_3\rightarrow Fe(NO_3)_3+3H_2O[/imath]
(15):[imath]2FeSO_4+2{{H_2SO_4}_{đặc nóng}}\rightarrow Fe_2(SO_4)_3 +2H_2O+SO_2\uparrow[/imath]

 

[Phương Dung]

Bài sửa:​

1.
(3) [imath]Ca(OH)_2+ Na_2CO_3 \to CaCO_3 + 2NaOH[/imath]
(5) [imath]Ca(HCO_3)_2 + 2HCl \to CaCl_2 + 2H_2O + 2CO_2[/imath]
2.
(10) [imath] Fe(OH)_3+ 3HNO_3 \to Fe(NO_3)_3 + 3H_2O [/imath]
(11) [imath] 2Fe(OH)_3 \overset{t^o}{\rightarrow} Fe_2O_3 + 3H_2O [/imath]
3.
(2) [imath]2SO_2 + O_2 \overset{450^o,V_2O_5}{\rightarrow} 2SO_3[/imath]
(4) [imath]H_2SO_4 + Na_2SO_3 \to Na_2SO_4 + H_2O + SO_2[/imath]
[imath]Na_2SO_3 + 2HNO_3 \to 2NaNO_3 + H_2O + SO_2[/imath]

 

[Minh Đăng]

BÀI SỬA​

Câu 2:
(2): \(FeCl_2 + 2AgSO_4 \to FeSO_4 + 2AgCl\downarrow;
(3): [imath]FeSO_4 + Ba(NO_3)_2 \to Fe(NO_3)_2 + BaSO_4\downarrow[/imath].
(7): \(FeCl_3 + 3AgSO_4 \to Fe_2(SO_4)_3 + 3AgCl\downarrow;
(10): [imath]Fe(OH)_3 + 3HNO_3 \to Fe(NO_3)_3 + 3H_2O[/imath].

 

[Ái Quỳnh]

BÀI SỬA:
Câu 2:
(2):[imath]FeCl_2 + Ag_2SO_4 \to FeSO_4 + 2AgCl[/imath]
(4): [imath]Fe(OH)_2 +Cu(NO_3)_2 \rightarrow Fe(NO_3)_2 +Cu(OH)_2\downarrow[/imath]
(7): [imath]2FeCl_3 + 3Ag_2SO_4 \to Fe_2(SO_4)_3+ 6AgCl[/imath]
(10):[imath]Fe(OH)_3+3HNO_3\rightarrow Fe(NO_3)_3+3H_2O[/imath]
(15): [imath]2FeSO_4+2{{H_2SO_4}_{đặc nóng}}\rightarrow Fe_2(SO_4)_3 +2H_2O+SO_2\uparrow[/imath]

 

[Hải Yến]

BÀI SỬA:
Câu 2:
(2):[imath]FeCl_2 + Ag_2SO_4 \to FeSO_4 + 2AgCl[/imath]
(4): [imath]Fe(OH)_2 +Cu(NO_3)_2 \rightarrow Fe(NO_3)_2 +Cu(OH)_2\downarrow[/imath]
(7): [imath]2FeCl_3 + 3Ag_2SO_4 \to Fe_2(SO_4)_3+ 6AgCl[/imath]
(10):[imath]Fe(OH)_3+3HNO_3\rightarrow Fe(NO_3)_3+3H_2O[/imath]
(15): [imath]2FeSO_4+2{{H_2SO_4}_{đặc nóng}}\rightarrow Fe_2(SO_4)_3 +2H_2O+SO_2\uparrow[/imath]

Quỳnh xem lại pt (4) nhé.

 

[Ái Quỳnh]

BÀI SỬA:
Câu 2:
(2): [imath]FeCl_2 + Ag_2SO_4 \to FeSO_4 + 2AgCl[/imath]
(4): [imath]Fe(OH)_2 +4HNO_3 \rightarrow Fe(NO_3)_3+3H_2O +NO_2[/imath]
(7): [imath]2FeCl_3 + 3Ag_2SO_4 \to Fe_2(SO_4)_3+ 6AgCl[/imath]
(10): [imath]Fe(OH)_3+3HNO_3\rightarrow Fe(NO_3)_3+3H_2O[/imath]
(15): [imath]2FeSO_4+2{{H_2SO_4}_{đặc nóng}}\rightarrow Fe_2(SO_4)_3 +2H_2O+SO_2\uparrow[/imath]